Subsections
11 Calorimetry
Heat is the energy transferred between systems at different
temperatures. Heat only describes energy transferred, and hence, we
do not speak of objects as containing heat. If heat flows from a table
top into a cold glass of water sitting on it, the internal energy of
the glass of water increases and the internal energy of the table top
decreases by the same amount. However, the temperatures of the two
systems does not in general change by the same amount. It is important
not to equate temperature with internal energy. Different
materials have different relationships between internal energy and
temperature.
The specific heat relates changes in internal energy to
changes in temperature. The specific heat
of a material is the
amount of energy in Joules required to raise the temperature of one
kilogram of a given material by one Celsius degree. A quantity of heat
flowing into an object of mass
and specific heat
is
related to the resulting change in temperature by
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(55) |
Changes of phase involve the absorption or release of energy. For
example, it costs a certain amount of energy to break the bonds
between the molecules in an ice crystal in order to turn it into
liquid water. The amount of energy in Joules released or absorbed per
kilogram of material in a particular change of phase is called the
heat of transformation
of that phase change. The heat of
transformation associated with the change from solid to liquid phase
is known as the heat of fusion, and the heat of
transformation associated with the change from liquid to vapor phase
is known as the heat of vaporization.
The heat flowing into or out of an object of mass
as a result of a
phase change with heat of transformation
is given by
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(56) |
Phase changes happen at fixed temperatures, so there is no temperature
change in the expression for the heat of transformation. In changes
from solid to liquid or from liquid to vapor phases, heat flows into
the system. In the reverse of these transitions, heat flows out of the
system.
The law of conservation of energy dictates that there is no net heat
flow within a closed system,
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(57) |
For example, if I submerge an ice cube in water in a Styrofoam cup and
allow them to come to the same temperature, the heat flowing out of
the water must equal the heat flowing into the ice cube to the extent
that no heat is gained or lost to the surrounding environment.
You will apply the law of conservation of energy to an approximately
closed system - a calorimeter. You will determine the specific heats
of samples of three common elements by heating each sample and
combining it with cold water in a calorimeter and measuring the
changes in temperature of the calorimeter, water, and sample. You will
also determine the densities of the samples. Then, you will try to
identify the samples based on your results.
You have been provided with an alcohol thermometer and two temperature
probes. Check the temperature probe calibrations as follows.
- Get a cup of ice water and a cup of hot (
)
water from the front of the lab.
- Connect the two temperature probes to channels 1 and 2 of the
LabPro interface (labeled CH1 and CH2).
- Run Logger Pro. The program should automatically
recognize the temperature sensors and set up a graph of the two
temperatures vs. time.
- Place both temperature probes and the alcohol thermometer in the
hot water and press the Collect button
. Stir the
water with the probes for about 10 seconds until the temperature
readings reach a constant value, and compare the temperature probe
readings with the temperature indicated by the alcohol thermometer.
- Repeat this process with the ice water.
- If there is significant disagreement, ask your instructor or TA
for help.
You have been provided with three cylindrical samples of
different materials suggestively labeled
,
, and
.
- Make whatever measurements you need to make in order to
determine the densities of the samples, and the associated
uncertainties, as precisely as you can. (Note that the hooks can be
removed from the samples.)
- Measure the mass of the dry calorimeter cup.
- Place about 100 mL of cold water and one of the temperature
probes in the calorimeter cup, and install the calorimeter cup in
its housing.
- Collect some hot (
) water from the
container at the front of the lab in a plastic cup. Place one of the
three samples in the hot water along with the other temperature
probe.
- Reduce the temperature of the water and
calorimeter cup to about
with the help of some
ice. Remove any solid ice from the water before proceeding.
- Start a long (5 minutes is plenty) measurement with
Logger Pro.
- Collect data for at least 10 seconds to establish the starting
temperatures of the hot water and the calorimeter.
- Using the piece of string tied to the hot sample, transfer it
to the calorimeter. Leave the hot temperature probe in the
hot water.
To minimize energy losses to the environment, avoid
touching the sample, and transfer it to the calorimeter as
quickly as possible.
- Stir the water in the calorimeter with the cold temperature
probe, and continue collecting data until the system reaches a
stable equilibrium temperature, and then save your measurement.
- Measure the mass of the water and calorimeter cup so that you
can determine the mass of water you used.
- Repeat this process with the other samples.
- Make several repeated measurements of the sample that causes the
largest change in temperature of the calorimeter.
- When you pull a sample out of the hot water, it carries some hot
water with it, mainly on top. Measure the mass of a wet sample to
determine how much water it carries. (You'll need this for the
individual assignment.)
The law of conservation of energy (Eq. 57) for the
calorimeter cup, the water, and the sample is given by
 |
(58) |
You have measured the masses as well as the initial and final
temperatures of all three objects. The calorimeter cup is aluminum
with specific heat
.
The specific heat of water is
.
- Solve Eq. 58 for
and set up a
spreadsheet to calculate the densities and specific heats of the
samples from your measurements.
- Use the repeated measurements you made of one sample to
determine the average value and the standard deviation of the mean
(SDOM).
- Use the ratio of the standard deviation of your repeated
measurements (not the SDOM) to the average value to assign
statistical uncertainties to your specific heat results for the other
samples.
- Each sample is made of a single element. Based on your
density and specific heat results, determine which elements are
compatible, within uncertainty, with your results for each
sample. (Refer to Appendix F of your text for densities and specific
heats.)
Show your work to your lab instructor and give preliminary answers to
questions
Hand in your spreadsheet and answers to the following questions.
- What elements are compatible with your density and specific heat
measurements of each sample? Explain.
- Why was it important to remove any solid ice from the
calorimeter in step 5 of the experiment?
- When you transferred the samples from the hot water into the
calorimeter, some hot water rode in on the sample. Estimate how large
a difference ignoring this small amount of hot water made in your
result for the specific heat of one of your samples. Show your work.
- Why did you use the standard deviation and not the SDOM of your
repeated measurements to assign uncertainties to the other samples in
step 3 of the analysis above?
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Copyright © 2003-2010, Lewis A. Riley
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Updated Fri Aug 27 11:05:11 2010
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This work is licensed under a Creative Commons License.